which of the following numbers are not in standard form (a)21.56×10 (b)215.6×10^4 (c) 2.156×10^6
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Prime factorizing 243, we get,
243=3×3×3×3×3=3
5
.
We know, a perfect cube has multiples of 3 as powers of prime factors.
Here, number of 3's is 5.
So we need to multiply another 3 in the factorization to make 243 a perfect cube.
Hence, the smallest number by which 243 must be multiplied to obtain a perfect cube is 3.
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