Math, asked by sibuspider, 8 months ago

Which of the following numbers are perfect cubes?
(i)4096
(ii)108
(iii)392
(iv)- 27000
(v)-64/1331​

Answers

Answered by PADMINI
2

Given:

i) 4096 (ii) 108 (iii) 392

(iv) 27000 (v) 64

1331

To Find :

Which of the given numbers are perfect cubes?

Solution :

1) 4096 (iv) 27000 (v) 64 (vi) 1331 are perfect cubes.

cube means we should multiply the number itself three times.

 =  >  {16}^{3}  = 16 \times 16 \times 16 = 4096

 =  >  {30}^{3}  = 30 \times 30 \times 30 = 27000

 =  >  {4}^{3}  = 4 \times 4 \times 4 = 64

 =  >  {11}^{3}  = 11 \times 11 \times 11 = 1331

Hence, 4096, 27000, 64 and 1331 are perfect cubes.

Similar questions