Math, asked by aadilrashidbhat2580, 1 month ago

Which of the following numbers is not a cube number?

(i) 10000

(ii) 3125

(iii) 64

(iv) 729​

Answers

Answered by Aryanpradhan47
25

Answer:

i) 10000

Step-by-step explanation:

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Answered by RvChaudharY50
3

Solution :-

Since we know that, for a perfect cube prime factors must be in pair of 3.

So, checking all given options we get,

a) 10000

→ 10000 = (2 * 2 * 2) * 2 * (5 * 5 * 5) * 5

as we can see that, prime factors of 10000 are not in pair of 3 . Therefore, 10000 is not a perfect cube .

b)

→ 3125 = (5 * 5 * 5) * 5 * 5

as we can see that, prime factors of 3125 are not in pair of 3 . Therefore, 3125 is not a perfect cube .

c)

→ 64 = (2 * 2 * 2) * (2 * 2 * 2)

we can see that, prime factors of 64 are in n pair of 3 . Therefore, 64 is a perfect cube .

d)

→ 729 = (3 * 3 * 3) * (3 * 3 * 3)

we can see that, prime factors of 729 are in n pair of 3 . Therefore, 729 is a perfect cube .

Hence, (i) 10000 and (ii) 3125 are not perfect cubes .

Learn more :-

(3) निम्न के स्थानीय मान लिखिये-

(अ)43.24

(स)884.20

(ब) 534.34

(द) 178.34

https://brainly.in/question/37666224

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