Question

Which of the following option is INCORRECT. [Atomic mass of Br = 80]
[Take H2O to be solvent in every case & solute is completely soluble]
(1) If mass fraction of CaBr2 and H20 are same, then molality of Cabra is 5m.
(2) If equal moles of NaCl and H20 are taken then, molality of NaCl is 55.55 m.
(3) If in place of NaCl we use NaBr as solute in option (B) then molality of NaBr solution changes.
If male fraction of NaCl is same as that of H20, then molality of NaCl will be 55.55 m.​

Answer 1

Answer:

b

jsjxjxksoiwytwcBniixh

Explanation:

hushahhshshhsh

jsjsjsjjzjjzjzhzuhdukalsdsagwahjre

hsjsjzjjzjB;89isihxhzhs

hshchhchchxn, n, n, nxnhzhzjysygya3yekhdiysiyjxyowoyslj lus

Answer 2

Answer:

Explanation:

For 1 mole H2O we have 1 mole NaCl

Here Molar mass of NaCl =58.5g

& molar mass of H20 = 18g

1 mole of NaCl for 18g of H20

For 1 kg you have= 1*1000/18 =55.6

At NTP density of water is

1000 gram/litre

and molecular mass of H2O = 18 grams

Density = mass / volume

Mole = mass / molar mass

Volume of water will be = mass of H2O/ density

Mass of H2O = Moles of H2O * Molar mass of H2O

= ( X *18 )

Volume = 18 X / 1000 litre

Thus

= 55.6 mol/lt