Question

Which of the following orbitals are not possible and why
1p,2s,2p,3f,3d,4f,4d

Answer 1

1p an 3f because in s subshell it contains maximum 2 electrons and in p subshell 2s and 2p both contains 8 electrons.. that's why 3f doesn't exist...

Answer 2

Answer: 1p and 3f are not possible.

Explanation:

Principle Quantum Numbers : It describes the size of the orbital and the energy level. It is represented by n. Where, n = 1,2,3,4....

Azimuthal Quantum Number : It describes the shape of the orbital. It is represented as 'l'. The value of l ranges from 0 to (n-1). For l = 0,1,2,3... the orbitals are s, p, d, f...

1. For 1 p:

n=1 and l can have value 0 to (n-1) i.e. 0 only. For p, l=1 which is not possible.

2. For 2s :

n=2 and l can have value 0 to (n-1) i.e. 0 and 1 only. For s, l=0 which is possible.

3. For 2p :

n=2 and l can have value 0 to (n-1) i.e. 0 and 1 only. For p, l=1 which is possible.

4. For 3f:

n=3 and l can have value 0 to (n-1) i.e. 0, 1 and 2 only. For f, l=3 which is not possible.

5. For 3d :

n=3 and l can have value 0 to (n-1) i.e. 0 , 1 and 2. For d, l=2 which is possible.

6. For 4f :

n=4 and l can have value 0 to (n-1) i.e. 0 , 1 , 2 and 3 For f, l=3 which is possible.

7. For 4d :

n=4 and l can have value 0 to (n-1) i.e. 0 , 1, 2 and 3 For d, l=2 which is possible.