Question

Which of the following orbitals has the lowest energy (4d,4f,5s,5p) ?

Answer 1

Answer:

5s

Explanation:

Energy of the orbital = (n+l)

where n= principal quantum number which is the shell number

l= azimuthal quantum number which is the subshell number

For 4d energy=4+2=6

For 4f energy= 4+3= 7

For 5s = 5+0=5

For 5p=5+1=6

The lowest of these is energy for 5s.

Answer 2

Answer:

Answer:

5s

Explanation:

Energy of the orbital = (n+l)

where n= principal quantum number which is the shell number

l= azimuthal quantum number which is the subshell number

For 4d energy=4+2=6

For 4f energy= 4+3= 7

For 5s = 5+0=5

For 5p=5+1=6

The lowest of these is energy for 5s