Chemistry, asked by smritirituraj12, 1 year ago

Which of the following order is not correct ?
A) Bond order: O2+ > O2> O2–> O22
B) Boiling point: HF >HCl>HBr> HI
C) Ionization energy: N > O and Be > B
D) Electronegativity: N > C > P >Si

Answers

Answered by tiwaavi
13
Hello Dear. :-)

→→→→→→→→→→→

Incorrect Answer is " A " ↔ Bond Order - O₂⁺ >O₂ > O₂⁻ > O₂²

It is incorrectly arranged Because It should be O₂²⁻ instead of O₂² .

 Explanation→→

A) Bond Order ⇒ O₂⁺ > O₂ > O₂⁻ > O₂²
 
Reason°
It is incorrect because the Correct bond Order is→ O₂⁺> O₂ >O₂⁻ >O₂²⁻ 
bond order decrease and the bond length increase in the given Order. Maximum the bond order , Maximum the Stability.



B) Boiling Point ⇒ HF > HCL > HBR > HI

Reason°
It is correct because Higher the strength of Acid, The Higher the Boiling Point So the strength of the Acid decreases in Halogens Family.



C) Ionization Energy ⇒ N> O and Be > B 

Reason°
It is Correct because Ionization energy , Increases with decrease in atomic radius across the period from left to right . Hence B is smaller then Be, so we expect increase in Ionization energy from Be to B . 



D) Electronegativity ⇒ N> C > P > Si

Reason°
It is correct because Electronegativity Increase along a period and Decrease down the group , Nitrogen is expected to have maximum Electronegativity. 


Hope it Helps.

Have a Marvelous Day.

Answered by IMrGauravI
2

Answer:

It is incorrectly arranged Because It should be O₂²⁻ instead of O₂² .

 Explanation→→

A) Bond Order ⇒ O₂⁺ > O₂ > O₂⁻ > O₂²

 

Reason°

It is incorrect because the Correct bond Order is→ O₂⁺> O₂ >O₂⁻ >O₂²⁻ 

bond order decrease and the bond length increase in the given Order. Maximum the bond order , Maximum the Stability.

B) Boiling Point ⇒ HF > HCL > HBR > HI

Reason°

It is correct because Higher the strength of Acid, The Higher the Boiling Point So the strength of the Acid decreases in Halogens Family.

C) Ionization Energy ⇒ N> O and Be > B 

Reason°

It is Correct because Ionization energy , Increases with decrease in atomic radius across the period from left to right . Hence B is smaller then Be, so we expect increase in Ionization energy from Be to B . 

D) Electronegativity ⇒ N> C > P > Si

Reason°

It is correct because Electronegativity Increase along a period and Decrease down the group , Nitrogen is expected to have maximum Electronegativity. 

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