which of the following oxidizing of nitrogen is an address of hn O3
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Therefore we can write the following equation for the oxidation states in HNO3: (H) + (N) + 3(O) = 0 Substitution of the known values for hydrogen and oxygen gives: (+1) + (N) + 3(-2) = 0 Solving for nitrogen: (N) = +5 Therefore the oxidation state of nitrogen in HNO3 is +5.
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