Question

which of the following pair is not isoelectronic---​

Answer 1

Answer:

(d) is the answer....

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Answer 2

$Na^+$ and Ne , $Al^{3+}$ and $B^{3+}$ and $P^{3-}$ and $N^{3-}$

Explanation:

Isoelectronic species are defined as the molecules which have the same number of electrons

1. $Na^+$ and Ne

Atomic number of sodium is 11 and thus has 11 electrons. $Na^{+}$ is formed by loss of 1 electron and thus has 10 electrons.

2. $Mg^{2+}$ and Ne

Atomic number of magnesium is 12 and thus has 12 electrons. $Mg^{2+}$ is formed by loss of 2 electrons and thus has 10 electrons.  Atomic number of neon is 10 and th}[/tex]us has 10 electrons.

Thus $Mg^{2+}$ and Ne are isoelectronic.

3. $Al^{3+}$ and $B^{3+}$

Atomic number of aluminium is 13 and thus has 13 electrons.$Al{^3+}$ is formed by loss of 3 electrons and thus has 10 electrons. Atomic number of boron is 5 and thus has 5 electrons. $B^{3+}$ is formed by loss of 3 electrons and thus has 2 electrons.

4. $P^{3-}$ and $N^{3-}$

Atomic number of nitrogen is 7 and thus has 7 electrons.$N^{3-}$ is formed by gain of 3 electrons and thus has 10 electrons.  Atomic number of phosphorous is 15 and thus has 15 electrons.$P^{3-}$ is formed by gain of 3 electrons and thus has 18 electrons.  

Learn More:

Calculation of electrons

https://brainly.com/question/2256682

Isoelectronic elements

https://brainly.com/question/13719095