Which of the following pair of concurrent forcess can not have a resultant of 4N?
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Answer:
3N and 8N
Explanation:
3N & 8N will give Fmax = 8 + 3 = 11N & Fmin = 8 - 3 = 5N .
The resultant force always lies between maximum & minimum value & 4 is outside the range. So 3N and 8N cannot give resultant as 4N.
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