Chemistry, asked by Rj2125, 1 year ago

Which of the following pairs have the same number of atoms?
(A) 64 grams of O2(g) and 4 grams of H2(g) (B) 64 g of SO2(g) and 44 g of CO2(g)
(C) 28 g of N2(g) and 32 g of O2(g)
$0) 65 g of Zn(s) and 23 g of Na(s)
Which of the followine atatamantlaliolara incorrect?​

Answers

Answered by IlaMends
7

Answer:

All the options are correct.

Explanation:

(A) 64 grams of O_2(g) and 4 grams of H_2(g).

Moles of oxygen gas =\frac{64 g}{32 g/mol}=2 mol

Number of molecules oxygen in 2 moles:

2\times 6.022\times 10^{23} molecules=1.02044\times 10^{24} molecules

Number oxygen atoms =2\times 1.02044\times 10^{24} molecules=2.04088\times 10^{24} molecules

Moles of hydrogen gas=\frac{4 g}{2 g/mol}=2 mol

Number of molecules hydrogen in 2 moles:

2\times 6.022\times 10^{23} molecules=1.02044\times 10^{24} molecules

Number hydrogen atoms =2\times 1.02044\times 10^{24} molecules=2.04088\times 10^{24} molecules

Number of oxygen atoms = Number of hydrogen atoms

(B) 64 g of SO2(g) and 44 g of CO2(g)

Moles of SO_2=\frac{64 g}{64 g/mol}=1 mol

Number of molecules SO_2 in 1 moles:

1\times 6.022\times 10^{23} molecules=6.022\times 10^{23}molecules

Total number of atoms in SO_2 :

3\times 6.022\times 10^{23}molecules=1.8066\times 10^{24} molecules

Moles of CO_2=\frac{44 g}{44 g/mol}=1 mol

Number of molecules CO_2 in 1 moles:

1\times 6.022\times 10^{23} molecules=6.022\times 10^{23}molecules

Total number of atoms in CO_2 :

3\times 6.022\times 10^{23}molecules=1.8066\times 10^{24} molecules

Number of SO_2atoms = Number of CO_2 atoms

(C) 28 g of N2(g) and 32 g of O2(g)

Moles of nitrogen gas =\frac{28 g}{28 g/mol}=1 mol

Number of molecules nitrogen 1 moles:

1\times 6.022\times 10^{23} molecules =6.022\times 10^{23} molecules

Number nitrogen atoms =2\times 6.022\times 10^{22} molecules=1.2044\times 10^{24} molecules

Moles of oxygen gas =\frac{32 g}{32 g/mol}= mol

Number of molecules oxygen in 1 moles:

1\times 6.022\times 10^{23} molecules=6.022\times 10^{23} molecules

Number oxygen atoms =2\times 6.022\times 10^{22} molecules=1.2044\times 10^{24} molecules

Number of nitrogen atoms = Number of oxygen atoms

D) 65 g of Zn(s) and 23 g of Na(s)

Moles of zinc =\frac{65 g}{65 g/mol}=1 mol

Number of molecules of zinc in 1 mole:

1\times 6.022\times 10^{23} molecules=6.022\times 10^{23} molecules

Number zinc atoms =\times 6.022\times 10^{22} molecules=6.022\times 10^{23} molecules

Moles of sodium=\frac{23 g}{23 g/mol}=1 mol

Number of molecules sodium in 1 mole:

1\times 6.022\times 10^{23} molecules=6.022\times 10^{23} molecules

Number sodium atoms =\times 6.022\times 10^{22} molecules=6.022\times 10^{23} molecules

Number of zinc atoms = Number of sodium atoms

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