Question

Which of the following pairs of compounds has same mole percent of carbon? C2H2 & C6H6 C2H4 & C3H8 CH4 & C6H12 C6H6 & C10H8

Answer 1

Answer:

hey mate here is your answer

Explanation:

c2h2

Answer 2

(i) C2H2 (Acetylene) & C6H6 (Benzene)

(iii) CH4 (methane & C6H12 (Cyclohexane)

Explanation:

Given:

(i) C2H2 (Acetylene) & C6H6 (Benzene)

(ii) C2H4 (Ethylene) & C3H8 (Propane)

(iii) CH4 (methane & C6H12 (Cyclohexane)

(iv) C6H6 (benzene) & C10H8 (naphthalene)

Find: Which pair of compounds has same mole percent of carbon?

Solution:

(i) Molar mass of acetylene = 12*2 + 1*2 = 26 g/mole

Mass of carbon in acetylene = 24

∴ % composition of the Carbon = 24/26 * 100 = 92.3%

Molar mass of the Benzene = 12*6 + 1*6 = 78 g/mole.

Mass of the Carbon Present in Benzene = 72

∴ % composition of the Carbon = 72/78 * 100 = 92.3%

(ii) Molar mass of the Ethylene = 12*2 + 1*4 = 28 g/mole.

Mass of the Carbon Present in Ethylene = 24

∴ % composition of the Carbon = 24/28 * 100 = 85.71%

Molar mass of the Propane = 12*3 + 1*8 = 44 g/mole.

Mass of the Carbon Present in Propane = 36

∴ % composition of the Propane = 36/44 * 100 = 81.82%

(iii)  Molar mass of the methane = 12*1 + 1*4 = 28 g/mole.

Mass of the Carbon Present in methane = 24

∴ % composition of the Carbon = 24/28 * 100 = 85.71%

Molar mass of the Cyclohexane = 12*6 + 1*12 = 84 g/mole.

Mass of the Carbon Present in Cyclohexane = 72

∴ % composition of the Carbon = 72/84 * 100 = 85.71%

(iv)  Molar mass of the benzene = 12*6 + 1*6 = 78 g/mole.

Mass of the Carbon Present in benzene = 72

∴ % composition of the Carbon = 72/78 * 100 = 92.3%

Molar mass of the naphthalene = 12*10 + 1*8 = 128 g/mole.

Mass of the Carbon Present in naphthalene = 120

∴ % composition of the Carbon = 120/128 * 100 = 93.7%

We find that

(i) C2H2 (Acetylene) & C6H6 (Benzene)

(iii) CH4 (methane & C6H12 (Cyclohexane)

have the same % composition of the Carbon.