Question

Which of the following paramagnetic ions would exhibit a magnetic moment (spin only) of the order of 5 BM ? (a) V2+ (b)Ti2+ (c)Mn2+ (d)Cr2+

Answer 1

Answer:

We know that ion electronic magnetic configuration magnetic moment will be $\sqrt{n(n+2)}$ .

Where n is the number of unpaired electrons.

Then number of unpaired electrons in the following compound will be 3 for vanadium(+2), 2 for titanium(+2) , 5 for manganese(+2), and will be 4 for chromium(+2).

Hence, by putting all in the equations we will get chromium's magnetic moment to be 4.9 which is nearest to 5 hence it will have magnetic moment of the order 5 BM.

Answer 2

Answer:Cr+2

Explanation:

V2+ [Ar]4s 0 3d 3 n=3

Ti2+ [Ar]4s0 3d2 n=2

Mn2+ [Ar]4s0 3d5 n=5

Cr2+ [Ar]4s 0 3d 4 n=4

Hence spin moment of Cr2+ = 4(4+2) ≈ 4.92BM ≈ 5BM

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