Question

Which of the following particles will describe the smallest circle when projected with the same velocity perpendicular to a magnetic field?
(a) Electron
(b) Proton
(c) He+
(d) Li+

Answer 1

Answer:

electron

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Answer 2

(a) When projected with the same velocity perpendicular to a magnetic field, electron will describe the smallest circle.

 Explanation:

• The required centripetal force for a particle when it moves in a circle in a magnetic field is given by the magnetic force.  
• So, by equating the centripetal force with the Lorentz force for a charged particle, we get: r = mvqB
• Here, v denotes velocity and m denotes mass. For all the given particles, the amount of charge is the same. It is to be noted that of all the particles, electron is the lightest particle. When projected with the same velocity, it describes the smallest circle perpendicular to the magnetic field.