Physics, asked by AaishaFathzz6211, 10 months ago

Which of the following particles will describe the smallest circle when projected with the same velocity perpendicular to a magnetic field?

Answers

Answered by poornavarshithaa00
0

Hey given "Which of the following", then it should have some options.

Where are they??

Answered by preethisatsangi
1

Answer:  I think u wanted to know this only...

Which of the following particles will describe the smallest circle when projected with the same velocity perpendicular to a constant magnetic field?

A. Electron

B. Proton

C. He+

D. Li+

I HOPE iT WiLL HeLp U  :}

Explanation:In the options given election has a lowest charge.

Electron < Proton < He+ <Li++

Formula used: The magnetic force is given by

F = qvBsinФ              ( here Ф= 90°, sin90°= 1)

Where F is magnetic force

q is electric charge =

1.6×10∧-19

v is velocity

B is magnetic field

F=mv^2/r

m is mass of the charge particle

v is velocity

r is radius of the projectile motion  

mv^2/r = qvB

mv^2 = rqvB

mv = rqB

r = mv/qB

Here v and B are constants and q is same for all the charge particles. r is proportional to m. If radius is small radius will become small. Electron exhibits light weight among the all other charge particles. Because of light weight it will creates a circle with a small radius when it is projected. So option A is correct.

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