Question

Which of the following points lies on the circle of radius 10 with centre at (4, -3)? ​

Answer 1

Answer:

The equation is: \frac{(x - 0)^{2} }{10^{2} } + \frac{(y - 0)^{2} }{10^{2} } = 1102(x−0)2+102(y−0)2=1

= \frac{x^{2} }{10^{2} } + \frac{y^{2} }{10^{2} } = 1102x2+102y2=1

A) \frac{(\sqrt{10}) ^{2} }{10^{2} } + \frac{(0)^{2} }{10^{2} } = 1102(10)2+102(0)2=1

⇒ \frac{10}{100}10010 + 0 = 1   FALSE

B) \frac{(0) ^{2} }{10^{2} } + \frac{(2\sqrt{5})^{2} }{10^{2} } = 1102(0)2+102(25)2=1

⇒ 0 + \frac{20}{100}10020 = 1   FALSE

C) \frac{(5\sqrt{2}) ^{2} }{10^{2} } + \frac{(5\sqrt{2})^{2} }{10^{2} } = 1102(52)2+102(52)2=1

⇒ \frac{50}{100}10050 + \frac{50}{100}10050 = 1   TRUE

Step-by-step explanation:

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