Question

which of the following points represents the center of a circle whose equation is (x-3)^2+(y-2)^2=16

a. (-3,-2)

b. (3,-2)

c. (-3,2)

d. (3,2)

Answer 1

Step-by-step explanation:

(x-3)^2+(y-2)^2=16

equation of circle : (x-a)^2 + (y-b)^2 = r^2

center = (a,b) = (3,2)

radius = 4

Answer 2

Answer:

option D

Equation of the circle is

(x-3)²+ ( y -2)²= 16

we find the vertex of circle by taking X=0 and Y=0 in equation of circle, means

( x -3)=0

x =3

(y -2)=0

y =2

therefore the centre of circle is ( 3,2)