Question

Which of the following polynomials has -3 as a zero -

i) (x-3)
ii) x^2-9
iii) x^2-3x
iv) x^2+3​

Answer 1

Answer:

ii)

$x {}^{2} - 9$

iii)

$x {}^{2} - 3x$

Step-by-step explanation:

substitute -3 in

$x {}^{2} - 9$

=(-3) ^2-9

=9-9=0.

Therefore, -3 is zero of x^2-9.

Now, substitute -3 in

$x {}^{2} - 3x$

=(3) ^2-3(3)

=9-9

=0.

Therefore, -3 is zero of x^2-3x.

Hope this helps you...