Chemistry, asked by gagusimran, 1 year ago

Which of the following processes involves absorption of energy and why?
a) Cl --> Cl-
b)O- --> O2-
c) O+ --> O-
d) S --> S-

Answers

Answered by sarvesh9smartpeg0nd
3
i think it is a because cl is a noble gas and invovles abdorption of energy

gagusimran: Cl is a noble gas?? Is it so. I have learnt it a halogen
sarvesh9smartpeg0nd: it want to become noble gas by adding one more electron
sarvesh9smartpeg0nd: every element want to remain stable
gagusimran: Yeah I know that but directly you wote cl to be a noble gas so i misunderstood. But the ans is 2 .why am not getting now
gagusimran: *wrote
sarvesh9smartpeg0nd: ok if you answer why you are time wasting
gagusimran: In the solution it is given. But am not getting the reason. And by the way I am not wasting any time . If you think I'm wasting your time then please no need to help if you dont want to do so.
sarvesh9smartpeg0nd: hey sorry dont miss understand me
sarvesh9smartpeg0nd: i want to help you
ranihasina: wrong answer dude
Answered by itemderby
7

Answer: Option (c) is correct.

Explanation:

In case of O^{+} \rightarrow O^{-},

The electronic configuration of O^{+} is 1s^{2}2^{2}2p^{3} and as the p sub shell is half filled, it will be stable.

Therefore, in order to become O^{-}, more energy needs to be provided. Hence, conversion of O^{+} \rightarrow O^{-} will involve absorption of energy.

In case of O^{-} \rightarrow O^{2-}, the electronic configuration of O^{-} will be 1s^{2}2^{2}2p^{5}. Therefore, in order to complete the octet O^{-} will readily accept an electron. Hence, there will be release of energy.

Whereas, the size of chlorine is large so it will readily lose an electron to become Cl^{-} so there will be release of energy.

Similarly, the size of sulfur is large as compared to oxygen so, it will readily lose an electron to become S^{-}. Hence, there will be absorption of energy.

Thus, it can be concluded that the conversion of O^{+} \rightarrow O^{-} involves absorption of energy.

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