Question

Which of the following quadratic equations has (x - 5) as a root? O x-1/X = 4 O x-1/x = 5 O X-5/X = 4 O X - 5/X = -5​

Answer 1

Answer:

Which one is the quadratic equation? 5/x - 3 = x^2 x (x + 5 ) = 2 n - 1 = 2n 1/x^2 (x + 2 ) = 2

Answer 2

x-5 is the root of the equation $x-\frac{5}{x} = 4$

Step-by-step explanation:

The root is x-5, hence (x = 5) should satisfy the given equations.

1. $x-\frac{1}{x} = 4$

substituting the value of x as 5 on the left-hand side, we obtain

$5-\frac{1}{5}$ $=\frac{24}{5}$ which is not equal to the right-hand side(4), hence (x-5) is not the root of this equation.

2. $x-\frac{1}{x} = 5$

substituting the value of x as 5 on the left-hand side, we obtain

$5-\frac{1}{5}$ $=\frac{24}{5}$ which is not equal to the right-hand side(5), hence (x-5) is not the root of this equation.

3. $x-\frac{5}{x} = 4$

substituting the value of x as 5 on the left-hand side, we obtain

$5-\frac{5}{5}$ $= 4$ which is equal to the right-hand side, hence (x-5) is the root of this equation.

4. $x-\frac{5}{x} = -5$

substituting the value of x as 5 on the left-hand side, we obtain

$5-\frac{5}{5}$ $= 4$ which is not equal to the right-hand side(-5), hence (x-5) is not the root of this equation.