Question

Which of the following reactions will yield
2, 2-dibromopropane?
(a) CH₃ – CH = CH₂ + HBr →
(b) CH₃ – C ≡ CH + 2HBr →
(c) CH₃CH = CHBr + HBr →
(d) CH ≡ CH + 2HBr →

Answer 1

The reaction (b) CH₃ – C ≡ CH + 2HBr → will yield 2,2-dibromopropane as:

1. In first step one HBr molecule will attack 2nd carbon atom of propyne according to Markovnikov's rule to form 2-Bromopropene.

2. In second step other HBr molecule will attack 2-Bromoproene again according to Markovnikov's rule to form 2,2-dibromopropane.

Answer 2

CH₃ – C ≡ CH + 2HBr will lead to 2, 2 - dibromopropane.

Explanation:

• The reactant is the propyne.

• The reagent is hydrogen bromide.

• Hydrogen halides are the good reagents for electrophilic addition reactions and the reactant propyne has two double bonds.

• So the proton from HBr will attack one of the double bonds and it will form the more stable secondary carbocation.

• So the first product will be 2 bromo propene.

• This reaction maintains the Markovnikov's rule of addition.

• The next reaction will follow the same rule, and form 2,2 dibromo propane.

For more information about markonikoff addition,

https://brainly.in/question/7788419

Give mechanism of Markovnikov addition. - Brainly.in

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Anti markovnikov addition of hbr is not observed in which of ...