Question

Which of the following relation holds true for an
equilibrium reaction, if its reaction quotient
(Q) = 1?
(1) AG = 0
(2) AG° = 0
(3) AG > AG°
(4) AG = AG°

Answer 1

The correct answer is option (4).

• We know that the relation between ΔG and Q is given by,

ΔG = ΔG° + RT ln (Q)        → eq(1)

Here, ΔG is change in free energy.

ΔG° is standard free energy change.

Q is reaction quotient.

R is gas constant and T is temperature.

• Now, we are given in the question that Q = 1

If we put this value in eq(1),

we get,

ΔG = ΔG° + RT ln (1)

Here, we know that ln(1) = 0.

So,

ΔG = ΔG° + RT x 0

ΔG = ΔG° + 0

ΔG = ΔG°

which is given in option (4)

Hence correct answer is option (4)

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