Question

Which of the following sequences are A.P.?9,13,17,21,25 are A.P.​

Answer 1

Step-by-step explanation:

9,13,17,21,25

a = 9

t2 = 13

t3 = 17

d = t2-t1 = 13-9 = 4

d = t3 -t2 = 17 -13 = 4

since common difference is same so they are in A. P

Answer 2

$\Large{\underline{\underline{\bf{Solution :}}}}$

As, we have to tell whether the sequence is A.P or not.

We know that,

When the common difference of the sequence is same then it is in A.P and if common difference is not same then the sequence is not in A.P

$\rule{200}{2}$

First term (t1) = 9

Second term (t2) = 13

Third term (t3) = 17

$\sf{T_2 - T_1 = T3 - T2} \\ \\ \sf{→13 - 9 = 17 - 13} \\ \\ \sf{→4 = 4} \\ \\ \sf{\therefore \: Common \: Difference \: is \: same \: then \: it \: is \: an \: A.P}$