Physics, asked by patrickjaison, 9 months ago

Which of the following sets of displacements might be capable of returning a car to its starting point ?
(A) 4, 6, 8 and 15 km
(B) 10, 30, 50 and 120 km
(C) 5, 10, 30 and 50 km
(D) 40, 50, 75 and 200 km

And please provide solution​

Answers

Answered by mufeedhapc256
7

Answer:

option A

Explanation:

condition

S1+S2+S3 > S4

here, only option A satisfies the given condition..!!

hope this helps..

Answered by mohnishkrishna05
0

Answer:

mark me as brainliest and the thank me if the answer is useful.

Explanation:

A car can return to its starting point, only when the sum of three displacements is greater than the value of the maximum displacement. In any other case, this would not be possible.

It has been given that a set of displacements has been arranged such that a car would be able to come back to its starting point.

For the second set, we have 10,30,50 and 120 km. The maximum value of displacement is 120km. Even if the car travels in a straight line, the sum of the first three displacements shall be,

10+30+50=90km.

The sum of the three displacements is less than the value of the maximum displacement. 90km<120km.

Thus, it cannot be possible.

For the third set, we have 5,10,30 and 50 km. The maximum value of displacement is 50km. Even if the car travels in a straight line, the sum of the first three displacements shall be,

5+10+30=45km.

The sum of the three displacements is less than the value of the maximum displacement. 45km<50km.

Thus, it cannot be possible.

For the fourth set, we have 40,50,75 and 200 km. The maximum value of displacement is 200km. Even if the car travels in a straight line, the sum of the first three displacements shall be,

40+50+75=165km.

The sum of the three displacements is less than the value of the maximum displacement. 165km<200km.

Thus, it cannot be possible.

For the first set of displacements, we have 4,6,8 and 15 km.The maximum value of displacement is 15km. Even if the car travels in a straight line, the sum of the first three displacements shall be,

4+6+8=18km.

The sum of the three displacements is more than the value of the maximum displacement. 18km>15km.

Thus, this is the only case where this set of displacements might be capable of bringing a car to its starting point.

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