Which of the following sets of quantum
numbers are not possible?
(A) n = 3,l = 2, m = 0, s =-1/2
(B) n = 4,l = 2, m = -1, s = -1/2
(C) n = 2,l = 0, m = -1,s = +1/2
(D) n= 3,l = 1, m = -1,s =-1/2
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Answer:
(i) n=3l=0,m=0s=
2
+1
(ii) 3sn>l
n
=l
So, not possible.
(iii) 4f possible.
(iv) Not possible
For s,m=0(always)
(v) not possible
l=2 i.e d cannot have m=−3
m for d is −l to +l i.e −2 to +2
So, the correct option is C
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