Question

which of the following solution has normality equal to molarity​

Answer 1

Answer:

3) HNO3 has molarity equal to Normality.

Normality = Molarity × Basicity.

For HNO3 Basicity is 1.

So N = 1×1 =1N.

Explanation:

Answer 2

Answer:

The correct answer is Option C: $HNO_3$

Explanation:

Let us take a look at all the given options.

(I) $H_2SO_4$

n-factor for $H_2SO_4=2$

$2H^+$ are seperable

Therefore, $N\neq M$

(II) $H_3PO_4$

n-factor for $H_3PO_4=3$

Therefore, $N\neq M$

(III) $HNO_3$

n-factor for $HNO_3=1$

Therefore, normality $=$ molarity $*1$

Hence, $N= M$

(IV) $Mg(OH)_2$

This is a salt.

For salts, n-factor is equal to the total charge on cations or total charge on anions.

Hence, n-factor $=2$

Therefore, $N\neq M$

• The number of moles of solute per litre of solution is called molarity.

• The number of equivalents per litre of solution is known as normality.

N-factor:

• In chemistry, the N factor is crucial for numerical problems.
• Acid basicity is measured by its N-factor.
• It is the outcome of product of normality and molarity.
• The N-factor aids in calculating a compound's gram equivalent.
• The n-factor of a molecule is its total H+ ion as indicated in the reaction.