Which of the following solutions have same molarity
(a)90g of Glucose in 500 ml of water
(b)8 g of NaOH in 200 ml of water
(c)49 g of H2SO4 in 250 ml of water
(d) 0.5 moles of NaCl in 500 ml of water
Answers
Answer:
b)8 g of NaOH in 200 ml of water
Answer:
Molarity, M=
Molarity, M= volume(L)
Molarity, M= volume(L)no. of moles
Molarity, M= volume(L)no. of moles
Molarity, M= volume(L)no. of moles
Molarity, M= volume(L)no. of moles Volume, V=250mL=0.25L
Molarity, M= volume(L)no. of moles Volume, V=250mL=0.25LNo. of moles, n= mass/molar mass
Molarity, M= volume(L)no. of moles Volume, V=250mL=0.25LNo. of moles, n= mass/molar massMass = 49 g
Molarity, M= volume(L)no. of moles Volume, V=250mL=0.25LNo. of moles, n= mass/molar massMass = 49 gMolar mass of H
Molarity, M= volume(L)no. of moles Volume, V=250mL=0.25LNo. of moles, n= mass/molar massMass = 49 gMolar mass of H 2
Molarity, M= volume(L)no. of moles Volume, V=250mL=0.25LNo. of moles, n= mass/molar massMass = 49 gMolar mass of H 2
Molarity, M= volume(L)no. of moles Volume, V=250mL=0.25LNo. of moles, n= mass/molar massMass = 49 gMolar mass of H 2 SO
Molarity, M= volume(L)no. of moles Volume, V=250mL=0.25LNo. of moles, n= mass/molar massMass = 49 gMolar mass of H 2 SO 4
Molarity, M= volume(L)no. of moles Volume, V=250mL=0.25LNo. of moles, n= mass/molar massMass = 49 gMolar mass of H 2 SO 4
Molarity, M= volume(L)no. of moles Volume, V=250mL=0.25LNo. of moles, n= mass/molar massMass = 49 gMolar mass of H 2 SO 4 = 98 g
Molarity, M= volume(L)no. of moles Volume, V=250mL=0.25LNo. of moles, n= mass/molar massMass = 49 gMolar mass of H 2 SO 4 = 98 gn=49/98=0.5
Molarity, M= volume(L)no. of moles Volume, V=250mL=0.25LNo. of moles, n= mass/molar massMass = 49 gMolar mass of H 2 SO 4 = 98 gn=49/98=0.5M=0.5/0.250=2M
Molarity, M= volume(L)no. of moles Volume, V=250mL=0.25LNo. of moles, n= mass/molar massMass = 49 gMolar mass of H 2 SO 4 = 98 gn=49/98=0.5M=0.5/0.250=2MHence, option A is correct.
Explanation:
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