Question

Which of the following species will be formed/deposited at cathode on
the electrolysis of an aqueous solution of potassium bromide?​

Answer 1

Explanation:

During electrolysis of aqueous NaCl solution, at cathode hydrogen is obtained from water and at anode, chlorine is obtained from NaCl.

During electrolysis of copper sulphate solution with platinum electrodes, at anode, oxygen is evolved from water and at cathode, copper is deposited.

During electrolysis of dilute aqueous sulfuric acid solution, water dissociates to form hydrogen and oxygen. Hydrogen is evolved at cathode and oxygen is evolved at anode.

During electrolysis, one species is reduced and other species is oxidized. Thus all electrolytic reactions are redox reactions.

Answer 2

Answer:

Potassium will be deposited at cathode during the electrolysis of an aqueous solution of Potassium bromide.

Explanation:

Electrolysis is a process in which ionic compounds get dissociated into their respective ions. At cathode, cations are reduced whereas anions are oxidized at anode.

Potassium bromide (KBr) will get dissociated into cation K+ and anion Br-

Hence, Potassium ion (K+) will get deposited at cathode.