Question

Which of the following statement is correct
A.6w² - 13w - 28 = (3w-4)(2w+7)
B.4w² + 20w + 25 = (2w + 5)²
C.6w² +5wx + x² = (2w - x)(3w - n)
D.16w² - 40w + 25 = (4w - 5)(4w - 5)

Answer 1

Given :

A.6w² - 13w - 28 = (3w-4)(2w+7)

B.4w² + 20w + 25 = (2w + 5)²

C.6w² +5wx + x² = (2w - x)(3w - x)

D.16w² - 40w + 25 = (4w - 5)(4w - 5)

To Find :  Correct statement

Solution:

A.6w² - 13w - 28 = (3w-4)(2w+7)

RHS =  (3w-4)(2w+7)

= 6w²  + 21w - 8w - 28

= 6w²  +  13w - 28

≠ LHS

B.4w² + 20w + 25 = (2w + 5)²

RHS = (2w + 5)²

= 4w² + 20w + 25

= LHS

Option B is correct

C.6w² +5wx + x² = (2w - x)(3w - x)

RHS = (2w - x)(3w - x)

= 6w²  - 5wx + x²

≠ LHS

D.16w² - 40w + 25 = (4w - 5)(4w - 5)

LHS = (4w - 5)(4w - 5)

= 16w² - 40w + 25

= RHS

Option D is correct

Hence Option B and  Dare correct

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