Math, asked by ks854092, 1 month ago

which of the following statement is false? (1)cube of any number is an odd number.
(2) A perfect cube does not end with two zeros
(3) A cube of single digit number may be a single digit number.
(4) There is no perfect cube with end with 3.​

Answers

Answered by msonu181181
0

Answer:

2) A perfect cube does not end with two zeros . This one is false.

3) A cube of single digit number may be a single digit number. This one is also false .

Step-by-step explanation:

hope it helps you

Answered by akshitaanand0301
0

Answer:

1. FALSE 2. FALSE 3.FALSE 4. FALSE

Step-by-step explanation:

1) cube of 3 = 3 × 3 × 3 = 27 which is odd number

cube of 2 = 2 × 2 × 2 = 8 which is an even no.

2) there are perfect cubes like 8 and 1728 that end with 8.

3) It is also a three digit number. Hence, the cube of a single digit number may be a single, double and three digit number. 4) If we take cube of 3=3×3×3=27

which does not end in 4

But for cube of 4 =4×4×4=64 which ends in 4.

There exists a number which ends in 4.

There is no perfect cube which ends in 4 is false.

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