which of the following statement is incorrect about the reaction of an alkyl ether with hydroiodic acid?
a]the reaction produces a aldehyde
B]the reaction goes via carbocation intermediate
C]the reaction produces alcohol
D] The reaction involves an oxonium ion
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Answer:
(A) the reaction produce a aldehyde
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The following statement is incorrect about the reaction of an alkyl ether with hydroiodic acid : a]the reaction produces a aldehyde.
- When alkyl ether is reacted with HI acid then the product will formed will be alcohol (propan-2-ol) not the aldehyde .
- It can either follow the SN¹ or SN² mechanism .If primary or methyl ether present then SN2 and the oxonium ion will be form in the transition state. But if tertiary alkyl ether then SN¹ and intermediate form will be carbocation.
- It aslo involves the oxonium ion means oxygen having the positive charge on it.
- Now see the reaction to understand in the better way.
SN¹
(CH3)3-O-CH2CH3 —> (CH3)3+ + CH3CH2O-
↓H-I
(CH3)3-I + CH3CH2OH
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