Question

Which of the following statements are correct?
1. The hybridisation in the cation of solid PCI, is sp3
II. In AB, E, type molecule, the B-A-B bond angle is always greater than the tetrahedral angle (E-lone
pair)
III. In CIO, NH, and XeOg, the hybridisation and number of lone pairs on the central atom are same
IV. In P, molecule there are six P-P bonds and four lone pairs of electrons
1) I, II and III
2) I, III and IV
3) III and IV
4) All are correct​

Answer 1

Explanation:

Which of the following statements are correct?

1. The hybridisation in the cation of solid PCI, is sp3

II. In AB, E, type molecule, the B-A-B bond angle is always greater than the tetrahedral angle (E-lone

pair)

III. In CIO, NH, and XeOg, the hybridisation and number of lone pairs on the central atom are same

IV. In P, molecule there are six P-P bonds and four lone pairs of electrons

1) I, II and III

2) I, III and IV answer

3) III and IV

4) All are correct

Answer 2

Statements I, III, and IV are correct. Thus, the correct option is Option 2.

• Statement I is correct. The hybridization in the cation of solid PCI₅ is sp3. The cation of PCl₅ is [PCl₄]⁺. It is tetrahedral in shape and has the hybridization sp³. The structures of the cation and anion of PCl₅ fit in to form a stable solid structure.
• Statement III is correct.  In CIO₃, NH₃, and XeO₃, the hybridization and number of lone pairs on the central atom are the same.
• Statement IV is also correct. Hence, each P atom has one lone pair of electrons and each covalent bond (includes two electrons) will be formed. Therefore, in total there will be 4 lone pairs of electrons and six P-P single bonds in a molecule of white phosphorus.
• Thus, statements I, III, and  IV are correct.