Which of the following statements is correct for the reaction: Al + HCl → AlCl 3 + H 2 (Given, the atomic mass of Al is 27 g) [0.8 mark]
1)The reaction equation follows the law of conservation of mass.
2) If 27 g of Al combines with 36.5 g of HCl, it will produce 133.5 g of A l C l 3 and 2 g of H 2
3)If 54 g of Al combines with 219 g of HCl, it will produce 267 g of A l C l 3 and 6 g of H 2
. 4)The given reaction is an example of a combination reaction.
Answers
Answer:
2)
Explanation:
1) Reaction does not follow law of conservation of mass as it is not balanced.
2) It is right.
3) Wrong as it does not follow law of conservation of mass.
4) Reaction is displacement reaction.
Answer:
2Al(s)
+
6HCl(aq)
→
2AlCl
3
(
aq
)
+
3H
2
(
g
)
Explanation:
Al(s)
+
HCl(aq)
→
AlCl
3
(
aq
)
+
H
2
(
g
)
is unbalanced.
Balance Cl.
There are 3 Cl atoms on the product side and 1 on the reactant side. Add a coefficient of 3 in front of
HCl
.
Al(s)
+
3HCl(aq)
→
AlCl
3
(
aq
)
+
H
2
(
g
)
There are now 3 Cl atoms on both sides.
Balance H.
There are 3 H atoms on the reactant side and 2 on the product side. 3 and 2 are multiples of 6. So change the coefficient in front of HCl from 3 to 6, and add a coefficient of 3 in front of the
H
2
.
Al(s)
+
6HCl(aq)
→
AlCl
3
(
aq
)
+
3H
2
(
g
)
There are now 6 H atoms on both sides.
Go back to the Cl. There are now 6 Cl on the reactant side and 3 on the product side. Add a coefficient of 2 in front of
AlCl
3
.
Al(s)
+
6HCl(aq)
→
2AlCl
3
(
aq
)
+
3H
2
(
g
)
There are now 6 Cl atoms on both sides.
Balance the Al
There is 1 Al on the reactant side and 2 Al on the product side. Add a coefficient in front of Al on the reactant side.
2Al(s)
+
6HCl(aq)
→
2AlCl
3
(
aq
)
+
3H
2
(
g
)
There are now 2 Al on both sides and the equation is balanced.
Reactants:
2 Al atoms
,
6 H atoms
,
6 Cl atoms
Products:
2 Al atoms
,
6 H atoms
,
6 Cl atoms
Answer link
Explanation:
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