Which of the following statements is wrong about 4.4 g of Co2
A) A = 0.1 mole of Co2
B) A = 100 ml at STP
C) A occupies 6.023*10^-23
D) 6 g C= 16 g of O2
Answers
Answered by
2
B, C are incorrect.
Let's see All options and determine whether which option is correct.
A) We know that
Gram molecular weight of Co2 =12+32 = 44g
1 mole of Co2 ----> 44 g
x moles ------> 4.4 g
4.4 = 44x
x = 44/440=1/10=0.1 moles.
Hence, If A is 4.4 g of Co2, then A = 0.1 mole of Co2.
Hence, Option A ✓.
===================================
B) We know that 1 mole of Co2 = 22,400 ml
Here given 0.1 moles of Co2 [ as per calculations in Option A.
so, 1 mole of Co2 = 22400 ml
0.1 mole of Co2 = x ml
x =0.1*22400
x = 2240 ml.
Hence, Option B is incorrect.
==================================
C) We know that 1 mole of Co2 = 6.023*10^23 particles.
0.1 moles = 6.023*10^23/10 = 6.023*10^22 particles.
Hence, A occupies 6.023 * 10^22 particles.
Hence Option C is wrong.
==================================
D) In Co2
1 mole of C combines with 1 mole of Co2
12 g of C combines with 32 g of Co2
Given, Weight of C =6 g.
6 g of C = x g of O2
12x =32*6
x =32*1/2
x =16 g.
Hence, 6 g of C combines with 16 g of O2.
Option D is correct.
=================================
The wrong statements are Option B,C
Let's see All options and determine whether which option is correct.
A) We know that
Gram molecular weight of Co2 =12+32 = 44g
1 mole of Co2 ----> 44 g
x moles ------> 4.4 g
4.4 = 44x
x = 44/440=1/10=0.1 moles.
Hence, If A is 4.4 g of Co2, then A = 0.1 mole of Co2.
Hence, Option A ✓.
===================================
B) We know that 1 mole of Co2 = 22,400 ml
Here given 0.1 moles of Co2 [ as per calculations in Option A.
so, 1 mole of Co2 = 22400 ml
0.1 mole of Co2 = x ml
x =0.1*22400
x = 2240 ml.
Hence, Option B is incorrect.
==================================
C) We know that 1 mole of Co2 = 6.023*10^23 particles.
0.1 moles = 6.023*10^23/10 = 6.023*10^22 particles.
Hence, A occupies 6.023 * 10^22 particles.
Hence Option C is wrong.
==================================
D) In Co2
1 mole of C combines with 1 mole of Co2
12 g of C combines with 32 g of Co2
Given, Weight of C =6 g.
6 g of C = x g of O2
12x =32*6
x =32*1/2
x =16 g.
Hence, 6 g of C combines with 16 g of O2.
Option D is correct.
=================================
The wrong statements are Option B,C
Deekshii1:
thq
Answered by
1
hey,
i think option B is right
because in this qustion no condition was given.......
i think option B is right
because in this qustion no condition was given.......
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