Question

Which of the following triplets are Pythagorean?
(i) (14, 48, 50)
(ii) (18, 79, 82)

Answer 1

Answer:

2k, (k

2

+1) and (k

2

−1) form a Pythagorean triplet for any number, k > 1

Let 2k=14

Hence, k=7

and, k

2

+1=7

2

+1=49+1=50

and, k

2

−1=7

2

−1=49−1=48

Check the answers: 14

2

+48

2

=196+2304=2500=50

2

Hence, the triplet is 14,48,50

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Answer 2

Answer:

2k, (k2+1) and (k2−1) form a Pythagorean triplet for any number, k > 1

Let 2k=14

Hence, k=7

and, k2+1=72+1=49+1=50

and, k2−1=72−1=49−1=48

Check  the  answers: 142+482=196+2304=2500=502

Hence, the triplet is 14,48,50