Math, asked by alokkashyap1999, 10 months ago

Which of the following values is closest to k when k=(1+\frac{1}{n})^n, given n is equal to the number of seconds in one year?

Answers

Answered by sonuvuce
5

k is closest to e

Step-by-step explanation:

Given

k=(1+\frac{1}{n})^n

Where n is the number of seconds in one year

Number of seconds in a year

=365\times 24\times 60\times 60

=32061600

Thus,

k=(1+\frac{1}{32061600})^{32061600}

We know that

 \lim_{n \to \infty} (n+\frac{1}{n})^n=e

Since 32061600 is sufficiently large number

Therefore, we can say that

k\approx e

or k\approx 2.72

Hope this answer is helpful.

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