Question

Which of the following weighs the least?
(A) 0.2 g atom of N (at. wt. N=14)
(C) 1 mole atoms of S (at. wt. S=32)
(B) 3x1023 atoms of C (at. wt. C = 12)
(D) 7 g silver (at. wt. Ag=108)​

Answer 1

Explanation:

Smaller is the number of moles present in an atom smaller will be its mass. Therefore, we will calculate the number of moles of given elements as follows.

No. of moles = \frac{\text{mass}}{\text{molar mass}}

molar mass

mass

(a) 2 g atom of Nitrogen

No. of moles = \frac{\text{mass}}{\text{molar mass}}

molar mass

mass

= \frac{2 g}{14 g/mol}

14g/mol

2g

= 0.142 mol

(b) 3 \times 10^{23}3×10

23

atoms of C

No. of moles = \frac{3 \times 10^{23}}{6.022 \times 10^{23}}

6.022×10

23

3×10

23

= 0.498 mol

(c) 1 mole of S

As 1 mole of every substance contains 6.022 \times 10^{23}6.022×10

23

atoms. Therefore, 1 mole of sulfur also contains 6.022 \times 10^{23}6.022×10

23

atoms.

(d) 7 g of Ag

No. of moles = \frac{\text{mass}}{\text{molar mass}}

molar mass

mass

= \frac{7 g}{107.86 g/mol}

107.86g/mol

7g

= 0.064 mol

Answer 2

Answer:

D)7 g silver (at. at. At=108)

Explanation:

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