Question

which of the following will have largest no.of atoms 1g of Na, 1g of O2, 2g of H2, 1g of Li​

Answer 1

Answer:

Hence, 1 g of Li (s) will have the largest number of atoms.

Answer 2

Answer:

$\huge \mathfrak \purple{Answer✓}$

(i) 1 g Au = 1/197 mol = 1/197×6.022×1023 atoms

(ii) 1 g Na = 1/23 mol = 1/23×6.022×1023 atoms

(iii) 1 g Li = 1/7 mol = 1/7×6.022×1023 atoms

(iv) 1 g Cl2 = 1/71 mol = 1/71×6.022×1023 atoms

• Hence, 1 g of Li has the largest number of atoms.

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