Which of the following would reacts with CH3MgI to give butan-2-ol?
a) Propanal b) Ethanal c) Ethanol d) Propan-2-ol
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Answer:
Propanal reacts with CH3MgI to give Butan-2-ol
Explanation:
Aldehydes react with Grignard reagent (RMgX) to give secondary (2°) alcohols.
RMgX: R = Alkyl group, X = Halogen
Here, R = CH3 and X = I
Propanal + Methyl magnesium iodide = Butan-2-ol
CH3-CH2-CHO + CH3MgI = CH3-CH2-CH(OH)-CH3
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