Question

Which of the maximum number of molecule?

Answer 1

Number of molecules present in 36 g of water = 36/18×N A = 2N A Number of molecules present in 28 g of CO = 28/28×N A = N A Number of molecules present in 46 g of C2H5OH = 46/46×N A = 2N A Number of molecules present in 54 g of N2O5 = 54/108×N A = 0.5N A Here N A is Avogadro's number.

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Answer 2

Answer:

Multiply the number of moles by the Avogadro constant, 6.022 x 10^23, to calculate the number of molecules