Question

which of the most electropsitive metal from Li,Na,K,Rb​

Answer 1

Answer:

The alkali metals are the most electropositive. Cesium is the most electropositive of the stable elements. Francium, while unstable, is theoretically the most electropositive element. Electropositivity increases down groups and decreases along periods (from left to right) on the periodic table.

Answer 2

Among the given metals, the most electropositive metal is $Rb$. Therefore, the correct answer is $Rb$.

Explanation:

• The elements of group 1 of the Modern Periodic table are called alkali metals.
• Alkali metals have one electron in their valence shell. This electron is one more than the noble gas configuration.
• This electron is loosely bonded to the nucleus and can be lost.
• Therefore, alkali metals have a tendency to lose one electron to attain a noble gas configuration.
• When alkali metals lose one electron, they acquire one unit positive charge and are represented as $\[{M^ + }\]$.
• Thus, they readily lose an electron and exhibit electropositivity.
• Electropositivity is the tendency of an atom to lose an extra electron.
• This electropositive nature of alkali metals increases down the group, i.e., the alkali metals that lie at the bottom in the group are more positive.
• Among $\[Li,Na,Ka,Rb\]$, $Rb$ lies at the bottom.
• Therefore, the tendency to lose an electron is more in $Rb$.
• Hence, it is the most electropositive metal among the given alkali metals.

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