Question

Which of the polynomial has -3 has zero? A.x-3 B.x^2-9 C.x^2-3x D.x^2+3

Answer 1

Answer:

option B

Step-by-step explanation:

by substituting-3 in x²-9

we get -(3)²-9= 9-9

= 0

Answer 2

Answer:

hope this helps u

Step-by-step explanation:

let us consider

x = -3

when we sub x = -3 the final answer will be zero

A) x - 3 = -3-3 = -6 ≠0

B)x²-9  = [-3]²-9 = 9-9 = 0

C) x²-3x = [-3]²-3*-3 =9+9 = 18≠0

D) x²+3 = [-3]²+3 = 3+3 = 6≠0

p(x) = x²-9 will have -3 as zero