Question

Which of the term of A.P 5,2, -1,........... is -49?

Answer 1

Answer:

a = 5 d= -3 now you can find it is easy now

Step-by-step explanation:

an= a+(n-1)*d

Answer 2

Given

• A.P = 5, 2, -1, ....

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To find

• Term at which A.P will be -49.

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Solution

• In this question, we have an A.P with

→ First term (a) = 5

→ Common difference (d) = -3

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• We have to find (n) required term.

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We know that

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$\star{\boxed{\boxed{\bf{a_n = a + (n - 1)d}}}}$

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• Let the $\sf{a_n}$ be -49.

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$\tt:\implies\: \: \: \: \: \: \: \: {-49 = 5 + (n - 1)(-3)}$

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$\tt:\implies\: \: \: \: \: \: \: \: {-49 - 5 = (n - 1)(-3)}$

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$\tt:\implies\: \: \: \: \: \: \: \: {-54 = (n - 1)(-3)}$

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$\tt:\implies\: \: \: \: \: \: \: \: {\dfrac{-54}{-3} = (n - 1)}$

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$\tt:\implies\: \: \: \: \: \: \: \: {n - 1 = 18}$

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$\tt:\implies\: \: \: \: \: \: \: \: {n = 18 + 1}$

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$\tt:\implies\: \: \: \: \: \: \: \: {n = 19}$

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Hence,

• 19th term of the given A.P is -49.