Question

Which of the transitions belong to lyman and balmer series ? calculate the ratio of the shortest wavelengths of the lyman and the balmer series of the spectra?

Answer 1

For transition we have the following formula

1/y = v = RZ^2[1/n1^2 - 1/n2^2]

here,
y = lambda = wavelength
v = nu bar = wave number
R = Rydberg constant = 109678 cm^-1
Z = Atomic number
n1 = on which transition will take place
n2 = from which transition will take place
for a particular series
n2>n1
for example:
s.no. series. n1 :: n2
1. Lyman. 1 :: 2,3,4....
2. Balmer. 2 :: 3,4,5...
3. Paschen. 3 :: 4,5,6....
4. Brackett. 4 :: 5,6,7.....
5. p-fund. 5 :: 6,7,8....

for wavelength

we have another formula

r = (n^2*h^2) ÷ (4 π^2.m.k.Z.e^2)
or
r = 0.529 * (n^2)/Z Angstrom

hope it helps. :-)