Question

Which of the two ions from the list given below have the geometry that is explained by the same hybridization of orbitals, $NO_2^-$, $NO_3^-$, $NH_2^-$, $NH_4^+$, SCN⁻ ?
(a) $NO_2^-$ and $NO_3^-$
(b) $NH_2^-$ and $NO_3^-$
(c) SCN⁻ and $NH_2^-$
(d) $NO_2^-$ and $NH_2^-$

Answer 1

the answer to this questions is

A

Answer 2

Answer:

The two ions from the list given below have the geometry that is explained by the same hybridisation of orbitals NO2-, NO3-, NH4+, SCN-  are NO2- and NO3-.

Explanation:

The two ions from the list given below have the geometry that is explained by the same hybridisation of orbitals NO2-, NO3-, NH4+, SCN-  are NO2- and NO3-.

This is because the both ions NO2- and No3- have the same hybridisation when compared to all the ions.

The hybridisation exhibited is sp2 type of hybridisation.