Question

Which of these are improper fractional numbers?Write where each of the improper fractional numbers would lie on the number line?
(i)2/7
(ii)7/11
(iii)9/11
(iv)13/2
(v)7/3

Answer 1

Answer:

13/2 & 7/3   are improper fractional numbers

13/2 will lie between 6 & 7

7/3 will lie between 2 & 3

Step-by-step explanation:

proper fractional numbers :  

A fraction where the numerator (the top number) is less than the denominator (the bottom number) is called proper fractional number.

improper fractional numbers :  

A fraction where the numerator (the top number) is greater than the denominator (the bottom number) is called improper fractional number.

and can be written as mixed fraction

13/2 & 7/3   are improper fractional numbers

13/2  = 6 1/2

so 13/2 will lie between 6 & 7

7/3 = 2 1/3  

so 7/3 will lie between 2 & 3

Proper fraction lies between 0 & 1

2/7 , 7/11 , 9/11

Answer 2

$\displaystyle\huge\red{\underline{\underline{Solution}}}$

CONCEPT TO BE IMPLEMENTED

FRACTION

Any fraction can be written as

$\displaystyle \sf{Fraction \: = \: \: \frac{ Numerator }{Denominator} }$

PROPER FRACTION

A fraction is said to be proper fraction if

Numerator < Denominator

IMPROPER FRACTION

A fraction is said to be improper fraction if

Numerator > Denominator

TO DETERMINE

To identify the improper fractions from the given numbers and to choose position of them in number line

Given Numbers are :

$\displaystyle \sf{ (i) \: \: \frac{2}{7} }$

$\displaystyle \sf{ (ii) \: \: \frac{7}{11} }$

$\displaystyle \sf{(iii) \: \: \frac{9}{11} }$

$\displaystyle \sf{(iv) \: \: \frac{13}{2} }$

$\displaystyle \sf{(v) \: \: \frac{7}{3} }$

CALCULATION

CHECKING FOR OPTION ( i )

$\displaystyle \sf{For \: the \: number \: (i) \: \: \frac{2}{7} }$

Numerator = 2

Denominator = 7

So, Numerator < Denominator

Hence the fraction is proper fraction

POSITION : It lies between 0 & 1

CHECKING FOR OPTION ( ii )

$\displaystyle \sf{For \: the \: number \: (i) \: \: \frac{7}{11} }$

Numerator = 7

Denominator = 11

So, Numerator < Denominator

Hence the fraction is proper fraction

POSITION : It lies between 0 & 1

CHECKING FOR OPTION ( iii )

$\displaystyle \sf{For \: the \: number \: (iii) \: \: \frac{9}{11} }$

Numerator = 9

Denominator = 11

So, Numerator < Denominator

Hence the fraction is proper fraction

POSITION : It lies between 0 & 1

CHECKING FOR OPTION ( iv )

$\displaystyle \sf{For \: the \: number \: (iv) \: \: \frac{13}{2} }$

Numerator = 13

Denominator = 2

So, Numerator > Denominator

Hence the fraction is improper fraction

POSITION : It lies between 6 & 7

CHECKING FOR OPTION ( v )

$\displaystyle \sf{For \: the \: number \: (v) \: \: \frac{7}{3} }$

Numerator = 7

Denominator = 3

So, Numerator > Denominator

Hence the fraction is improper fraction

POSITION : It lies between 2 & 3

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LEARN MORE FROM BRAINLY

The value of

0.854 (bar on 54)+0.23 (23 bar)-0.68 (bar 8)

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