Math, asked by akangkshya07, 3 days ago

Which of these is the HCF of 10 (x2 - y2) and 5 (-3x + 3y)?
1) x - y
2) - x + y
3) 5 (x - y)
4) 5 (x + y)​

Answers

Answered by pulakmath007
1

SOLUTION

TO CHOOSE THE CORRECT OPTION

Which of these is the HCF of

10 (x² - y²) and 5 (-3x + 3y)

1) x - y

2) - x + y

3) 5 (x - y)

4) 5 (x + y)

EVALUATION

Here the given two expressions are

10 (x² - y²) and 5 (-3x + 3y)

We now factorise them

First expression

= 10 (x² - y²)

= 2 × 5 × ( x + y ) × ( x - y )

Second expression

= 5 (-3x + 3y)

= - 5 ( 3x - 3y )

= - 5 × 3 × ( x - y )

= - 3 × 5 × ( x - y )

So the required HCF = 5 ( x - y )

FINAL ANSWER

Hence the correct option is 3) 5 (x - y)

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Answered by hidhi
0

Answer:

for the first one and the other is

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