Math, asked by lathaprabakaran5, 7 months ago

Which of these is the set of ALL 2-digit numbers whose digits add up to 7? 1) {70} 2) {16, 25, 34, 43} 3) {16, 25, 34, 43, 52, 61} 4) {16, 25, 34, 43, 52, 61, 70}

Answers

Answered by SɴᴏᴡʏSᴇᴄʀᴇᴛ
39

\huge\bold{\underline{\underline{\red{Answer}}}}

\sf{2\:digit\:number\:that\:adds\:upto\:7\:are}

\sf{16, 25, 34, 43, 52, 61, 70}

\sf{\orange{Method}}

There are seven such numbers. we can do this by simply finding two digits that will add up to 7 and combine them to form two-digit numbers.

This gives us 1 and 6, 2 and 5, 3 and 4, 7 and 0.

Combining these digits gives 16, 25, 34, and 70 but we can reverse some of these numbers to obtain different two-digit numbers.

Thus, 16 gives 61, 25 give 52, 34 gives 43. Note that it is not practical to reverse 70 to obtain 07(07 is simply 7).

Hence, we have 7 two-digit numbers with their digits summing up to 7.

Thus 16, 25, 34, 43, 52, 61 and 70

<marquee direction=right>

❤ᴍᴀɢɪᴄᴀʟᴘɪᴇ❤

Answered by aayan88
1

Answer:

There are seven such numbers. we can do this by simply finding two digits that will add up to 7 and combine them to form two-digit numbers.

This gives us 1 and 6, 2 and 5, 3 and 4, 7 and 0.

Combining these digits gives 16, 25, 34, and 70 but we can reverse some of these numbers to obtain different two-digit numbers.

Thus, 16 gives 61, 25 give 52, 34 gives 43. Note that it is not practical to reverse 70 to obtain 07(07 is simply 7).

Hence, we have 7 two-digit numbers with their digits summing up to 7.

Thus 16, 25, 34, 43, 52, 61 and 70

Similar questions