Question

Which one contains maximum number of molecules ?
(A) 2.5 g molecule of N,
(B) 4g atom of nitrogen
(C) 3.01 x 1024 atoms
(D) 82 g of dinitrogen​

Answer 1

Answer:

D

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Answer 2

(D) 82 grams of dinitrogen

GIVEN

(A) 2.5 g molecule of N,

(B) 4g atom of nitrogen

(C) 3.01 x 10²⁴ atoms

(D) 82 g of dinitrogen

TO FIND

Which of the substances contain maximum number of molecules.

SOLUTION

We can simply solve the above problem as follows;

We know that,

Molar mass of substance = 1 mole of substance = Nₐ

Where,

Nₐ = 6.022 × 10²³ .

(1) 2.5 g molecule of N₂

Molecular mass of N₂ = 28 grams

Number of molecules in 28 grams of N₂ = Nₐ

So,

Number of molecules in 2.5 grams of N₂ = (2.5/28)× Nₐ

= 0.08Nₐ

Number of molecules in 0.08 mole of N₂ = 0.08Nₐ

(2) 4g atom of nitrogen gas

We know that,

28 gram atom of N₂ = Nₐ

4 gram atom of N₂ = (Nₐ/28)×4 =

0.14 Nₐ

(3) 3.01 x 10²⁴ atoms

(4) 82 g of dinitrogen

28 grams of N₂ = Nₐ

82 grams of dinitrogen = (82/28)Nₐ = 2.92 Nₐ

We can observe that 82 gram of dinitrogen contains maximum molecules.

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