Which one has more Osmotic Pressure (O.P.) and why?
a) 1 M Glucose
b) 1 M NaCl
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Answers
Answered by
0
1 M NaCI
hope it helps....
hope it helps....
IshitaChakraborty:
How to calculate?
Answered by
3
the osmotic pressure for NaCL and glucose.
Osmotic pressure = icRT
where i = van't Hoff factor
c = concentration in molarity
R= gas constant; 0.08206atm-l/mole-K
T= temperature in kelvin
Since there is no temperature indicated, we will try to use 298K (or room temperature) for the both solutions.
for 1M glucose
Osmotic P = (1)(1mole/L) (0.08206atm-l/mole-K) (298K)
= 24.45atm
**van't Hoff factor (i)=1 because glucose do not dissociate into ions when it is in the solution.
for 1M NaCl
Osmotic P = (2)(1mole/L) (0.08206atm-l/mole-K) (298K)
= 24.45
= 48.91 atm
**van't Hoff factor (i)=2 because NaCl dissociates into ions when it is in the solution. NaCl ---> Na+ + Cl-
We can simply picture it out as: there are more particles in 1M NaCl than in 1M glucose because of dissociation.
so we can say that 1m NaCl is more hypertonic.
Osmotic pressure = icRT
where i = van't Hoff factor
c = concentration in molarity
R= gas constant; 0.08206atm-l/mole-K
T= temperature in kelvin
Since there is no temperature indicated, we will try to use 298K (or room temperature) for the both solutions.
for 1M glucose
Osmotic P = (1)(1mole/L) (0.08206atm-l/mole-K) (298K)
= 24.45atm
**van't Hoff factor (i)=1 because glucose do not dissociate into ions when it is in the solution.
for 1M NaCl
Osmotic P = (2)(1mole/L) (0.08206atm-l/mole-K) (298K)
= 24.45
= 48.91 atm
**van't Hoff factor (i)=2 because NaCl dissociates into ions when it is in the solution. NaCl ---> Na+ + Cl-
We can simply picture it out as: there are more particles in 1M NaCl than in 1M glucose because of dissociation.
so we can say that 1m NaCl is more hypertonic.
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